Tickets for all but 100 seats in a 10,000-seat stadium were

[BTGmoderatorDC]

Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of the tickets sold, 20% were sold at half price and the remaining tickets were sold at the full price of $2. What was the total revenue from ticket sales?

A. $15,840
B. $17,820
C. $18,000
D. $19,800
E. $21,780

OA B

Source: Official Guide

[GMATGuruNY]

Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of the tickets sold, 20% were sold at half price and the remaining tickets were sold at the full price of $2. What was the total revenue from ticket sales?

A. $15,840
B. $17,820
C. $18,000
D. $19,800
E. $21,780

If all 10,000 tickets are sold, we get:
20% sold for $1 each = 2000*1 = 2,000
80% sold for $2 each = 8000*2 = 16,000
Total revenue = 2000+16000 = 18,000
Since 100 tickets are not actually sold, the total revenue must be a bit less than 18,000.

The correct answer is B.

[swerve]

100 are not sold from 10,000

So seats sold\(=9900\)

\(20\%\) is 1980 and the remaining \(80\%\) is 7920.

Each ticket cost 2$ and 1980 cost 1$

So \(2*7920 +1980=17820\) is our answer \(\Rightarrow\) __B__

[Scott@TargetTestPrep]

Tickets for all but 100 seats in a 10,000-seat stadium were sold. Of the tickets sold, 20% were sold at half price and the remaining tickets were sold at the full price of $2. What was the total revenue from ticket sales?

A. $15,840
B. $17,820
C. $18,000
D. $19,800
E. $21,780

OA B

Source: Official Guide

We see that 10,000 - 100 = 9,900 tickets were actually sold.

0.2 x 9,900 = 1,980 tickets were sold for 1 dollar each, so these tickets generated 1,980 dollars in revenue.

9,900 - 1,980 = 7,920 were sold for 2 dollars each, so these tickets generated 15,840 dollars in revenue.

The total revenue earned was 1,980 + 15,840= 17,820 dollars.

Answer: B