why do we need stat 2 to solve this Q
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|x| = y-z?
(1)
x+y=z
if x>0, then x+y=z, or x=z-y, so |x| ≠ y-z
if x<0, then -x+y=z, or x=y-z, so |x| = y-z
INSUFF
(2)
x<0
noyhing about z and y
INSUFF
(1)(2)
x<0, then -x+y=z, or x=y-z, so |x| = y-z
SUFF
C
