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by smallsorrow » Tue Sep 30, 2008 9:32 am
A square playground has the same area as a rectangular playground that is 30 feet longer but 20 feet narrower. What is the length, in feet, of a side of the square playground?
A) 10 radical 5
B) 10 radical 6
C) 25
D) 50
E) 60

Is there a way to avoid the quadratic equation?
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Source: — Problem Solving |

by stop@800 » Tue Sep 30, 2008 9:38 am
yes

s2 will cancel out and thr will not be any quadretic

a*a = (a+30)(a-20)
solve it
a = 60 [a^2 on both sides will cancel out]
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by smallsorrow » Tue Sep 30, 2008 9:55 am
Ah ... Get it - did not see it this afternoon! Thanks!
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by vishubn » Tue Sep 30, 2008 10:00 am
yes,
kinda straight....

area of a sq=area of rect

L*L=(L+30)(L-20)
L^2=L^2-20L+30L-600
-20L+30L-600=0
L=60

Hope this helps

Vishu
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