3^6 - 1 = 3^6 - 1^6 = (3^3)^2 - (1^3)^2 = (3^3 - 1^3) * (3^3 + 1^3); applying a^2 - b^2 = (a - b)(a + b)swerve wrote:What is the greatest prime factor of 3^6 - 1 ?
A. 2
B. 3
C. 7
D. 13
E. 17
The OA is D.
Please, can any expert explain this PS question for me? I don't understand why that is the correct answer. Thanks.
(3^3 - 1^3) * (3^3 + 1^3) = [(3 - 1)(3^2 + 3*1 + 1^2)]*[(3 + 1)(3^2 - 3*1 + 1^2)] = 2*(9 + 3 =1)*4*(9 - 3 +1) = 2*13*4*7
We see that the greatest prime factor is 13.
The correct answer: D
Hope this helps!
-Jay
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