BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Six congruent circles are packed into an equilateral

Expert replies
by swerve » Tue Oct 23, 2018 12:11 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

Image

Six congruent circles are packed into an equilateral triangle so that no circle is overlapping and such that circles are tangent to one another or the triangle at any point of contact, as shown above. What is the area of the part of the triangle that is NOT covered by circles?

$$1. \text{ The radius of each circle is } 2.$$
$$2. \text{ The area of the triangle is } 48 + 28\sqrt{3}$$

The OA is D

Source: Veritas Prep
Join the discussion
Source: — Data Sufficiency |

swerve wrote:Image

Six congruent circles are packed into an equilateral triangle so that no circle is overlapping and such that circles are tangent to one another or the triangle at any point of contact, as shown above. What is the area of the part of the triangle that is NOT covered by circles?

$$1. \text{ The radius of each circle is } 2.$$
$$2. \text{ The area of the triangle is } 48 + 28\sqrt{3}$$
Source: Veritas Prep
$$?\,\,\, = \,\,\,{S_\Delta } - 6 \cdot {S_ \circ }$$
The GMATH widget (a.k.a "GW") is defined in the figure below. It is formed combining an equilateral triangle (side length 4r) and three "legs" (length r each), where r is any positive number.

Image

With the GW in mind, the answer is (D) immediately:

(1) The value of r is given, hence the corresponding GW is unique, hence the triangle that circumscribes the GW is unique (dotted triangle in the figure shown in the bottom-left). Our FOCUS is unique.

(2) The equilateral triangle is given, hence the corresponding inscribed GW is unique (dotted GW shown in the bottom-right), hence r is unique. Our FOCUS is unique.


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
Join the discussion