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permutation/combination

Expert replies
by vaibhav101 » Sat Sep 01, 2018 6:05 am

Timer

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Answers

A

B

C

D

E

Stats

Difficulty—

there are 5 rock songs, 6 carnatic songs and 3 indi pop songs . How many different albums can be formed using the above repertoire if the album should contain at least 1 rock song and 1 carnatic song?

A 15624
B 16384
C 6144
D 240
E 8123
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Source: — Problem Solving |

by deloitte247 » Sat Sep 08, 2018 10:33 am
There are 5 rock songs,
6 Carnatic songs, and
3 Indi pop songs
Each of these songs can either be included in the album or not included in the album, so we have the total of 2 options for each song.
For 5 rock songs in which the album must certain at least 1 rock song.
Total number of different rock songs combination in the album,
$$=\left(2^5\right)-1$$
=32 - 1 = 31 combinations,
Where at least one rock song is present in the albums.
For 6 Carnatic songs in which the album must curtain at least 1 Carnatic song;
Total number of different Carnatic songs combination in the album
$$=\left(2^6\right)-1$$
=64 - 1
= 63 combinations where at least one Carnatic song is present in the albums.
For 3 Indi pop songs in which each of them can either be included in the albums or not included,
Total number of different Indi pop songs combination in the album,
$$=2^3$$
= 8 combinations which includes one combination where none of the Indi pop songs is included in the album.
Total Albums = 31 * 63 * 8
= 15, 624

Option A is CORRECT.
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by Brent@GMATPrepNow » Sun Sep 09, 2018 9:27 am
vaibhav101 wrote:there are 5 rock songs, 6 carnatic songs and 3 indi pop songs . How many different albums can be formed using the above repertoire if the album should contain at least 1 rock song and 1 carnatic song?

A 15624
B 16384
C 6144
D 240
E 8123
This question is a little too ambiguous to be an official GMAT question.
Let's say X, Y and Z represents 3 different songs.
Is an album with song X first, song Y second and song Z third considered DIFFERENT FROM an album with song Z first, song X second and song Y third?
The answer to this question is not apparent in the wording.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Scott@TargetTestPrep » Mon Sep 17, 2018 5:31 pm
vaibhav101 wrote:there are 5 rock songs, 6 carnatic songs and 3 indi pop songs . How many different albums can be formed using the above repertoire if the album should contain at least 1 rock song and 1 carnatic song?

A 15624
B 16384
C 6144
D 240
E 8123
Each song can either be included in the album or excluded from the album, so each song has two choices. Since there are 14 songs, the number ways to form an album is 2^14 = 16,384 if there are no restrictions. (Notice that 2^14 is also equal to 2^5 x 2^6 x 2^3 where the exponents 5, 6 and 3 are the number of rock, carnatic, and indi pop songs, respectively.)

However, the album must contain at least 1 rock song and 1 carnatic song. Of the 2^5 = 32 ways to include any number (from 0 to 5) of rock songs, there is only 1 way that no rock song is included, so the number of ways to include at least 1 rock song is 32 - 1 = 31. Similarly, Of the 2^5 = 64 ways to include any number (from 0 to 6) of carnatic songs, there is only 1 way that no carnatic song is included, so the number of ways to include at least 1 carnatic song is 64 - 1 = 63. Note that there are no restrictions on the number of indi pop songs, so we have 2^3 = 8 ways to choose the indi pop songs. Therefore, the number of ways to include at least 1 rock song and 1 carnatic song in the album is:

31 x 63 x 8 = 15,624

Answer: A

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