M7MBA wrote:A bag has 4 blue, 3 yellow and 2 green balls. The balls of the same color are identical. In how many ways can a child picks ball(s) out of the bag? He could even decide to pick ZERO balls.
A. 60
B. 1260
C. 24
D. 120
E. 9
Number of options for the 4 blue balls = 5. (0, 1, 2, 3, or 4 blue balls may be chosen, for a total of 5 options.)
Number of options for the 3 yellow balls = 4. (0, 1, 2, or 3 yellow balls may be chosen, for a total of 4 options.)
Number of options for the 2 green balls = 3. (0, 1, or 2 green balls may be chosen, for a total of 3 options.)
To combine the options for each color, we multiply:
5*4*3 = 60.
The correct answer is
A.
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