M7MBA wrote:Is mn < 0? $$(1)\ \ \ m^5n^2<0$$ $$(2)\ \ \ m^{11}p^8n^5<0$$ The OA is the option B.
How can I know the sign of mn without knowing them? Experts, I would appreciate your help here.
Hello M7MBA.
Here is how I solved it.
$$(1)\ \ \ m^5n^2<0$$ implies that m^5<0 and then m<0. But, we don't know anything about n. Therefore this statement is NOT SUFFICIENT.
$$(2)\ \ \ m^{11}p^8n^5<0$$ Now, we can rewrite the given expression as follows: $$m^{11}p^8n^5=mn\left(m^{10}p^8n^4\right)=mn\left(m^5p^4n^2\right)^2<0\ \Rightarrow\ \ mn<0\ \ \Rightarrow\ SUFFICIENT.$$ In conclusion, the correct answer is the option
B. I hope it helps.