What is the maximum number os 27 cubic centimetre cubes...

[AAPL]

What is the maximum number of 27 cubic centimeter cubes that can fit in a rectangular box measuring 8-centimeter x 9-centimeter x 12-centimeter?

A. 36
B. 32
C. 24
D. 21
E. 15

The OA is C.

I tried the following,

(8*9*12) / (3*3*3) =

8/3 = 2 (Ignore decimal; SPACE utilized CANNOT be adjusted. That's wasted).

9/3 = 3

12/3 = 4

Then, 4*3*2 = 24.

Is there another strategic approach to solve this PS question? Can any experts help, please? Thanks.

[Jay@ManhattanReview]

What is the maximum number of 27 cubic centimeter cubes that can fit in a rectangular box measuring 8-centimeter x 9-centimeter x 12-centimeter?

A. 36
B. 32
C. 24
D. 21
E. 15

The OA is C.

I tried the following,

(8*9*12) / (3*3*3) =

8/3 = 2 (Ignore decimal; SPACE utilized CANNOT be adjusted. That's wasted).

9/3 = 3

12/3 = 4

Then, 4*3*2 = 24.

Is there another strategic approach to solve this PS question? Can any experts help, please? Thanks.

This is perfect.

-Jay
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[Jeff@TargetTestPrep]

What is the maximum number of 27 cubic centimeter cubes that can fit in a rectangular box measuring 8-centimeter x 9-centimeter x 12-centimeter?

A. 36
B. 32
C. 24
D. 21
E. 15

The 27 cubic centimeter cubes are 3 centimeters on each edge since 3^3 = 27. Since 8 is not a multiple of 3, we have to consider the dimension 8 of the box as 6, since 6 is a multiple of 3. Thus the "usable" volume of the box is 6 cm x 9 cm x 12 cm, and it can fit

(6 x 9 x 12)/27 = (54 x 12)/27 = 2 x 12 = 24 cubes

Answer: C