BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

A right circular cylinder of 72 cubic meters

Expert replies
by NandishSS » Thu Jan 18, 2018 4:48 am
A right circular cylinder of 72 cubic meters is completely filled with water. If water evaporates from the cylinder at a constant rate of two liters per hour per one square meter of surface, how long will it take for 30 liters of water to evaporate?

(1) The height of the cylinder is 2 meters.

(2) The radius of the base of the cylinder is 6/√π meters.

OA: D

HI Experts,

Can you please explain in detail?

Thanks
Nandish
Join the discussion
Source: — Data Sufficiency |

by ErikaPrepScholar » Thu Jan 18, 2018 6:38 am
We know the volume of the cylinder in question - 72 cubic meters. We need to find how long it takes for 30 liters to evaporate. HOWEVER, the rate of evaporation depends on the area of the surface of the water. This means we need to know the area of the surface - how big is the circle on top of the cylinder. We don't know this because our cylinder could have any proportions: our cylinder could be short and fat, tall and skinny, or somewhere in between, as long as it has a 72 cubic meter volume.

We know that the area of the circle must be A = πr^2. This means that if we know the radius of the cylinder, we can solve for area of the circle, which we can use to solve for rate of evaporation (rate = A in square meters * 2 liters/hour/square meter), which we can then use to solve for how long it will take to evaporate 30 liters. We also know that V = 72 = πr^2 * h, or because A = πr^2, V = 72 = A * h. This means that if we know the height of the cylinder, we can solve for area of the circle, then rate of evaporation, then length of time to evaporate 30 liters. So if we know either radius or height, the statement should be sufficient.

Statement 1 gives us height, so we know right away it is sufficient - no need to plug anything in. If we DID plug it in, we would get

$$72\ m^3=A\cdot2m$$ $$A=36m^2$$ $$36m^2\cdot2\frac{\frac{liters}{hour}}{m^2}$$ $$72\frac{liters}{hour}$$ $$\frac{30\ liters}{72\frac{liters}{hour}}=\frac{5}{12}hours$$

Statement 2 gives us radius, so it must be sufficient as well. But again, if we were to solve, we would get
$$A=\pi\left(\frac{6}{\sqrt{\pi}}m\right)^2=36m^2$$ $$36m^2\cdot2\frac{\frac{liters}{hour}}{m^2}$$ $$72\frac{liters}{hour}$$ $$\frac{30\ liters}{72\frac{liters}{hour}}=\frac{5}{12}hours$$

The correct answer is D.
Image

Erika John - Content Manager/Lead Instructor
https://gmat.prepscholar.com/gmat/s/

Get tutoring from me or another PrepScholar GMAT expert: https://gmat.prepscholar.com/gmat/s/tutoring/

Learn about our exclusive savings for BTG members (up to 25% off) and our 5 day free trial

Check out our PrepScholar GMAT YouTube channel, and read our expert guides on the PrepScholar GMAT blog
Join the discussion