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Cabbage shipments

Expert replies
by kobel51 » Wed Jan 15, 2014 7:26 am
A shipment of 1,500 heads of cabbage, each of which was approximately the same size, was purchased for $600. The day the shipment arrived, 2/3 of the heads were sold, each at 25 percent above the cost per head. The following day the rest were sold at a price per head equal to 10 percent less than the price each head sold for the day before. What was the gross profit on this shipment?

A) $100
B) $115
C) $125
D) $130
E) $135

Any useful shortcuts?
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Source: — Problem Solving |

by Patrick_GMATFix » Wed Jan 15, 2014 7:36 am
The solution below is taken from the GMATFix App.

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by Brent@GMATPrepNow » Wed Jan 15, 2014 7:43 am
kobel51 wrote:A shipment of 1,500 heads of cabbage, each of which was approximately the same size, was purchased for $600. The day the shipment arrived, 2/3 of the heads were sold, each at 25 percent above the cost per head. The following day the rest were sold at a price per head equal to 10 percent less than the price each head sold for the day before. What was the gross profit on this shipment?

A) $100
B) $115
C) $125
D) $130
E) $135
1,500 heads of cabbage purchased for $600
So, price per cabbage = 600/1500 = 6/15 = 2/5 = 0.4
So, each cabbage cost $0.40

2/3 of the heads were sold, each at 25 percent above the cost per head.
2/3 of 1500 = 1000. So, 1000 heads we sold.
25% of $0.40 = $0.10. So, the selling price = $0.40 + $0.10 = $0.50
Revenue = (1000)($0.50) = $500

The following day the rest were sold at a price per head equal to 10 percent less than the price each head sold for the day before
There are 500 heads remaining
10% of $0.50 = $0.05. So, the selling price = $0.50 - $0.05 = $0.45
Revenue = (500)($0.45) = $225

TOTAL REVENUE = $500 + $225 = $725

So, gross profit = $725 - $600 = [spoiler]$125 = C[/spoiler]

Cheers,
Brent
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by GMATGuruNY » Wed Jan 15, 2014 8:19 am
kobel51 wrote:A shipment of 1,500 heads of cabbage, each of which was approximately the same size, was purchased for $600. The day the shipment arrived, 2/3 of the heads were sold, each at 25 percent above the cost per head. The following day the rest were sold at a price per head equal to 10 percent less than the price each head sold for the day before. What was the gross profit on this shipment?

A) $100
B) $115
C) $125
D) $130
E) $135

Any useful shortcuts?
Since we need to calculate the profit for the ENTIRE shipment, we can plug in an EASIER VALUE for the number of heads.
Let the number of heads = 3.
Since the cost of the entire shipment is $600, the cost per head = 600/3 = $200.

2/3 of the heads were sold, each at 25 percent above the cost per head:
For these 2 heads, the selling price per head = 200 + (1/4)(200) = 250.
Profit per head = 250 - 200 = 50.
Total profit = 2*50 = 100.

The following day the rest were sold at a price per head equal to 10 percent less than the price each head sold for the day before.
Selling price for the 1 remaining head = 250 - (1/10)(250) = 225.
Profit = 225-200 = 25.

Total profit for all 3 heads = 100+25 = 125.

The correct answer is C.
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by Jeff@TargetTestPrep » Thu Dec 14, 2017 4:49 pm
kobel51 wrote:A shipment of 1,500 heads of cabbage, each of which was approximately the same size, was purchased for $600. The day the shipment arrived, 2/3 of the heads were sold, each at 25 percent above the cost per head. The following day the rest were sold at a price per head equal to 10 percent less than the price each head sold for the day before. What was the gross profit on this shipment?

A) $100
B) $115
C) $125
D) $130
E) $135
We are given that a shipment of 1500 heads of cabbage costs 600 dollars, or 600/1500 = $0.40 per cabbage.

We are given that 2/3 x 1500 = 1,000 heads of cabbage sold for 1.25 x $0.40 = $0.50. So, a total of 1,000 x $0.50 = $500 was made on the sale of those heads of cabbage.

The next day, 500 heads of cabbage were sold at a price of 0.9 x $0.50 = $0.45, so a total of 500 x $0.45 = $225 dollars was made on the sale of those heads.

Thus, a total of 500 + 225 = $725 was made.

Thus, profit = 725 - 600 = $125.

Answer: C

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