T-52:13

[camitava]

Guys, I dnt know whether this Qs has already been asked here! I tried to search in this forum but with no result. However, the Qs is -



OA is D

[stop@800]

slope = -3/5
and y intercept = 30

so eqn of line
3x+5y = 150

y = (150-3x)/5

for y to be integer x has to be multiple of 5
x varies from 0 to 50
so 11 possible values of x: 0 5 10 15 . . . . . 45

Whats the OA?

[camitava]

Got it sir! Yes the OA is D ...

[Indradeep]

It is 11 points because any point on the line (x,y) is in the ration of 5:3
Thus x = (5/3)y which is only possible if y = multiple of 3 from 0->30 including both, i.e. 11 points.
Thus D