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by cramya » Thu Sep 18, 2008 3:57 pm
Pick numbers and eleiminate the choices.

Since we are given 3 as the number we need to do most of our calculations with pick multiples of 3 as the 3 numbers and evaluate the choices

I first picked 3,6,9 and eliminated choice iii) and was down to 2 choices i) and ii). Then I picked three other numbers 6,12,15

Only ii) will always be true(Note:If the question read could be true then thats a whole different story based on the number choices you pick)

Also note sometimes when u pick numbers you could run in to the problem of 2 choices to be true. Then in this case to confirm if indeed this is going to be true for all cases pick 3 new numbers and test You could get lucky by picking the numbers where you would not be in a situation like me



I would say answer is B) II ONLY
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by ddm » Thu Sep 18, 2008 4:47 pm
OA - B
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by stop@800 » Thu Sep 18, 2008 10:46 pm
the qn talks about mean

only II will give us the mean
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