BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Q2- question on percent

Expert replies
by [email protected] » Mon Oct 17, 2016 7:17 am
"If there are 80% as many as boys as girls" - what does that mean? Does that mean 80% of boys and 80% of girls? Please look at the question below

75% of all boys and 48% of all girls of Smith High School takes civics. If there are 80% as many boys as girls, what percent of all students take civics?
Join the discussion
Source: — Problem Solving |

by Brent@GMATPrepNow » Mon Oct 17, 2016 7:29 am
[email protected] wrote:"If there are 80% as many as boys as girls" - what does that mean? Does that mean 80% of boys and 80% of girls? Please look at the question below

75% of all boys and 48% of all girls of Smith High School takes civics. If there are 80% as many boys as girls, what percent of all students take civics?
There are 80% as many as boys as girls
This means that: # of boys = 80% of the number of girls
That is: # of boys = (0.80)(# of girls)


75% of all boys and 48% of all girls of Smith High School takes civics. If there are 80% as many boys as girls, what percent of all students take civics?
Let G = number of girls
So 0.8G = number of boys

75% of all boys take civics
Number of boys taking civics = 0.75(0.8G) = 0.6G

48% of all girls take civics
Number of girls taking civics = 0.48G

Total number of children taking civics = 0.6G + 0.48G = 1.08G
Total number of children in the school = G + 0.8G = 1.8G

PERCENTAGE of children taking civics = (100)(1.08G)/(1.8G)
= (100)(1.08)/(1.8)
= 605

RELATED VIDEOS
- Introduction to percent: https://www.gmatprepnow.com/module/gmat ... video/1073
- Working with percent: https://www.gmatprepnow.com/module/gmat ... video/1074
- Finding x Percent of y: https://www.gmatprepnow.com/module/gmat ... video/1076
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by [email protected] » Mon Oct 17, 2016 7:44 am
Dear Brent,

if I can pick a smart number and based on the logic you stated, i.e.

That is: # of boys = (0.80)(# of girls)

can I say that if there are 100 girls, we have 80 boys? Can you please explain with a smart number?
Join the discussion