BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

% problems - Help needed

Expert replies
by bsharad_99 » Wed Aug 31, 2016 9:37 pm
If price decreases by 25%, by what % should consumption increase so that the expenditure does
not increase?
A) 33.33% b) 25% c) 43% d) 68% e) 65.55%

If speed increases by 33.33%, what is the percent reduction in the time taken to travel the same
distance?
A) 33.33% b) 25% c) 43% d) 68% e) 65.55%

The price of a product increased by 20% but the turnover increased by only 12%. What is the %
drop in quantity sales?
A) 33.33% b) 25% c) 43% d) 6.66% e) 65.55%
Join the discussion
Source: — Problem Solving |

by [email protected] » Thu Sep 01, 2016 9:57 am
Hi bsharad_99,

To start, you should list just one prompt per post - that way the conversation can stay focused on just one prompt and we can avoid the confusion of having multiple discussions on different questions in one thread.

As it stands, all 3 of these questions test the same concept and can all be solved by TESTing VALUES.

For the 1st question:

We're told that price decreases by 25%, and we're asked how much consumption needs to increase to create the same overall expenditure.

Original Price = $100
Total Consumption = $1,000
Units = 10

New Price = $75

(75)(X) = 1,000
X = 1,000/75 = 40/3 = 13.33333 units

% increase = (difference)/(original) = 3.3333/10 = 33.33%

Final Answer: A

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by Matt@VeritasPrep » Thu Sep 01, 2016 4:27 pm
bsharad_99 wrote:If price decreases by 25%, by what % should consumption increase so that the expenditure does
not increase?
A) 33.33% b) 25% c) 43% d) 68% e) 65.55%
Assuming that Price * Consumption = Expenditure (I have no idea if this is the equation, but it seems reasonable enough), we want

Old Expenditure = New Expenditure

or

Old Price * Old Consumption = New Price * New Consumption

or

p * c = (3/4)p * (x)c

Divide both sides by p * c

1 = (3/4) * x

4/3 = x

4/3 = 1 + (1/3), so we must increase by 33.33...%.
Join the discussion

by Matt@VeritasPrep » Thu Sep 01, 2016 4:28 pm
bsharad_99 wrote: If speed increases by 33.33%, what is the percent reduction in the time taken to travel the same
distance?
A) 33.33% b) 25% c) 43% d) 68% e) 65.55%
Distance = Rate * Time

Old Distance = New Distance, so

Old Rate * Old Time = New Rate * New Time, or

r * t = (4/3)*r * (x)*t

Divide both sides by r * t:

1 = (4/3) * x

3/4 = x

3/4 = 1 - 1/4, so time decreases by 25%.
Join the discussion

by Matt@VeritasPrep » Thu Sep 01, 2016 4:34 pm
bsharad_99 wrote:The price of a product increased by 20% but the turnover increased by only 12%. What is the %
drop in quantity sales?
A) 33.33% b) 25% c) 43% d) 6.66% e) 65.55%
I'd need the equation your textbook gives to relate price, turnover, and quantity. Is it Turnover = Sales/Inventory?
Join the discussion