number of crimes in city Y

[ManSab]

To decrease the number of crimes in city Y, the city's Police Commissioner proposed taking some police officers from low-crime districts of the city and moving them to high-crime districts of the city. His proposal is based on city Y crime data that show that the number of crimes in any district of the city decreases when additional police officers are moved into that district.

The Police Commissioner's proposal depends on which of the following assumptions?

1) City X experienced a drastic reduction in crime after implementing a proposal similar to that proposed by the Police Commissioner of city Y.

2) The severity of crimes committed in any district of the city decreases when additional police officers are moved into that district.

3)The number of crimes committed in all high-crime districts of city Y is more than triple the number of crimes committed in all low-crime districts of city Y.

4)There are more low-crime districts than high-crime districts in city Y.

5)Districts of the city from which police officers are removed do not experience significant crime increases shortly after the removal of those officers.

OA.. later
Please provide your answers with reasoning.

Thanks

[pandeyvineet24]

option E for me.

[ManSab]

pandeyvineet24 - Could you please explain how you reached to this assumption.

E....is correct.

Thanks

[gmat740]

If you negate E, then it will weaken the argument

lets take a look

5)Districts of the city from which police officers are removed do not experience significant crime increases shortly after the removal of those officers.

Districts of the city from which police officers are removed experience significant crime increases shortly after the removal of those officers.

So clearly the move was detrimental. Thus this is the assumption.

Hope this helps

[brick2009]

An assumption that has to be valid for the argument to hold good is:
If you reduce officers in one part of the city.... the crime in that part will not increase...

Also.. in the argument its is clearly stated that: High # of officers = Less crime...

Also simple elimination process:
a) City X? (out)
b.) no mention of severity in th argument... (out)
c.) Not abtout comparing number of crimes in Y..? (out)

d.) It is not abt number of lowe crime DISTRICTS? (out)
e.) Is the typical LMS (last man standing)..solution

[ManSab]

thanks gmat740 and brick2009.

[aj5105]

E.

[khanshainur]

I feel the answer will be E

[Eric77Gorm]

I would go with option E as the correct option