IF Y-X <0 then

[gmatrant]

If y-x <0 then
A. x>y
B. Both x and y are positive
C. Only one of the two is negative
D. x < y
E. None of the above.

Ans : E, how come shouldnt it be A.

[parallel_chase]

If y-x <0 then
A. x>y
B. Both x and y are positive
C. Only one of the two is negative
D. x < y
E. None of the above.

Ans : E, how come shouldnt it be A.

This is a must be true question. Therefore, the answer option should hold true for all cases.

A. x>y

y=2, x =4

2-4 = -2<0. Eliminate.

B. Both x and y are positive
Both positive holds true for above case,

y=-2, x=2

-2 - (+2) = -4<0. Eliminate.

C. Only one of the two is negative

after looking at above cases we can Eliminate this as well.

D. x < y

y=-3, x=-6
-6-(-3) = -6+3 = -3<0. Eliminate.

E. None of the above.

Since we are only left with this option. Answer is E.


Hope its clear.

[Ian Stewart]

The answer is certainly A; just add x to both sides of the inequality. Where is the question from?

[sumithshah]

Your reasoning appears wrong!

You are saying :

For A, X>Y

y=2, x =4

2-4 = -2<0. Eliminate - why eliminate? This is in accordance with the given condition

[parallel_chase]

Your reasoning appears wrong!

You are saying :

For A, X>Y

y=2, x =4

2-4 = -2<0. Eliminate - why eliminate? This is in accordance with the given condition

Absolutely Right!

Lesson learnt. Just have to be bit more careful the next time.

[sumithshah]

but then still doesn't solve the problem - the OA is E! or the OA is wrong.

where did you get this question from @ the guy who started this thread

[bhamav]

My vote is for A. There's no way that I can deduce E.

[karthikgmat]

Its very easy question to be answered.. Even a child answers it isn't it?
A is an apt choice.

[rajasiddarth]

to SumitShah!!!!!

y-x<0

y=2, x=4

-2<0

So, the condition is true.. thn how can you eliminate A??

[Stockmoose16]

I think the answer is A, too.

[gmatrant]

The question was given to me by a friend of mine.. sorry not sure from where..