3^8 - 2^8 is a difference of squares: it can be rewritten as (3^4)^2 - (2^4)^2.RobertP wrote:Hello everyone,
Can some one please help me understand the solution of the problem bellow?
Thank you!
If N = 3^8 - 2^8, which of the following is not a factor of n?
A) 97
B) 65
C) 35
D) 13
E) 5)
Answer: C
Because 3^4 = 81 and 2^4 = 16, (3^4)^2 - (2^4)^2 = 81^2 - 16^2.
Because x^2 - y^2 = (x+y)(x-y), 81^2 - 16^2 = (81 + 16)(81 - 16) = 97 * 65.
So clearly 97 and 65 are factors.
65 = 13*5, so 97*65 = 97*13*5; Therefore13 and 5 are factors.
That leaves us with C













