BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Data Sufficiency

Expert replies
by NarendraSure » Wed Jul 01, 2015 2:02 pm
Hi All,

One of my friend had asked me to solve the DS question attached in the picture, I wasn't able to solve it. can somebody help me understand how this one has to be tackled.

Regards
Naren
Attachments
GMAT_DS_Geometry.jpg
Join the discussion
Source: — Problem Solving |

by Ian Stewart » Wed Jul 01, 2015 2:24 pm
This is a GMATPrep question. There are several ways to solve, but if you can label an unknown angle with a letter in a question like this, and then use the basic angles facts to express every other angle in terms of that letter, you'll be able to answer any similar question, so that's the approach I'll use:

Statement 1 alone is not sufficient, because you can freely move point U around, and that changes the size of x. Similarly Statement 2 alone is not sufficient, because you can move point Q around and change x.

Using both Statements, say the angle at point R is y degrees. Then the angle at point T must be 90-y degrees, because in the big right triangle, the angles sum to 180.

Now Statement 1 tells us RQS is isosceles, so the angles at Q and S are equal. If the third angle in that triangle is y, then the two equal must sum to 180-y (because the sum of angles in a triangle is 180), so each angle is (180-y)/2 = 90 - (y/2)

Similarly, we know from Statement 2 that triangle TUS is isosceles. If the angle at T is 90-y degrees, the two equal angles must sum to 90+y degrees (because the sum of the three angles is 180). So each of the two equal angles is (90+y)/2 = 45 + (y/2)

Now we have labeled all three of the angles around point S -- they are 90 - (y/2), x, and 45 + (y/2). These angles form a straight line, so must add to 180. But notice what happens when we sum the three angles - the terms containing 'y' cancel out, and we get 135+x. So x must be 45 degrees, and the statements together are sufficient. The answer is C.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion

by NarendraSure » Wed Jul 01, 2015 2:58 pm
Hi Ian,

That helps a lot, thanks for explaining, I was doing it completely opposite, I took y = (180-2z), and hasn't considered t = 90-y.

once again thanks for the great reply.

Regards
Naren
Join the discussion

by nikhilgmat31 » Fri Jul 03, 2015 12:29 am
better to put DS question in its respective forum
Join the discussion