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GmatPrep Question...

Expert replies
by Fei » Mon Feb 26, 2007 5:36 am
Troubles here:

The rate of a chemical reaction is directly proportional to the square of the concentration of chemical A, and inversely proportional to the concentration of chemical B present.

If conentration of B is increased by 100%, which of the following is closest to percentage change in concentration of chemical A required to keep the rate unchanged.

Ans = +40%

Any help is qreatly appreciated...
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Source: — Problem Solving |

by banona » Mon Feb 26, 2007 11:27 am
The rate of a chemical reaction is directly proportional to the square of the concentration of chemical A, and inversely proportional to the concentration of chemical B present.

This means that the rate couldbe written as R =K * CA^2/CB
Where K is a constant
CA is the concentration ofchemical A
CB is the concentration ofchemical B

* If conentration of B is increased by 100%, it means that the

Let R1 = CA1^2/ CB1, be the rate befre CB changed
and R2 = CA2^2/ CB2, the rate after CB doubled ( increased by 100%)
To keep the rate unchanged, we would have to fit the following equation :
R1=R2, this means that CA2 ^2/CB2 = CA1^2/CB1

AS CB2 = 2 CB1
THEN, CA2^2 = 2 * CA1^2

CA2 = SQUARE Root of 2* CA1 = 1,4 CA1

tHIS MEANS THAT Ans = +40%


GOOD LUCK
I appologize for my Frenchy-English.
I am working on it.
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by Stacey Koprince » Mon Feb 26, 2007 11:01 pm
Please post the full text (including answers) any time you post a question. It is often the case that we can use the answers to decide which strategy is the best one to solve a particular question.
Thanks!
Please note: I do not use the Private Messaging system! I will not see any PMs that you send to me!!

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by aim-wsc » Tue Feb 27, 2007 6:12 am
hey
Fei, :)
How have you been?
Why do you still want to solve GMAT Math problems? ;) you are already done with it :lol:
Are you thinking of retaking it ? :|

As Stacey says we should provide the complete problem alongwith source of it. It's for good. 8)

Anyway it seems that bonana has already replied to you. :)
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by 800GMAT » Sun Apr 01, 2007 11:21 pm
I got the same question in my prep test.

R= [K(A^2)]/; where K is a constant.

In this question 3 answer choices can be eliminated without solving:

To keep the fraction constant, if the denominator is increased the numerator has to increase.
3 answer choices mentioned a decrease and hence can be eliminated

To calculate the percentage increase of A

B-->2B i.e. B changes from B to 2B
A^2--> 2.A^2 i.e. A^2 has to change from A^2 to 2.A^2

A^2 = 2. A^2
A = sqrt2. A

Thus, A has to increase to sqrt2.A

Percent increase from A to sqrt2.A is approx 40%
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