BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Number of People on a Bus

Expert replies
by chacha0212 » Wed Oct 08, 2014 5:03 pm
Half the people on a bus get off at each stop after the first, and no one gets on after the first stop. If only one person gets off at stop number 7, how many people got on at the first stop?

A. 128
B. 64
C. 32
D. 16
E. 8

Could you please help on this question? The answer says B and I did not understand the explanation.

Thanks!
Join the discussion
Source: — Problem Solving |

by [email protected] » Wed Oct 08, 2014 5:21 pm
Hi chacha0212,

Since the answer choices are numbers, one of those numbers MUST be the number of people who got on the bus at the first bus stop. This means we can TEST THE ANSWERS.

We're told that there were 7 stops (counting the first stop where people got ON the bus). We're also told that half the people who were on the bus got off at each ensuing bus stop, until the 7th stop where just 1 person got off.

Normally, it's best to TEST Answer B or D first, but I'm going to start with Answer A to prove a point/pattern:

If 128 get on the bus at the 1st stop....
2nd stop: 64 get off, 64 still on
3rd stop: 32 get off, 32 still on
4th stop: 16 get off, 16 still on
5th stop: 8 get off, 8 still on
6th stop: 4 get off, 4 still on
7th stop: 2 get off, 2 still on......

In this scenario, 2 people got off the bus at the 7th stop. The question tells us that only 1 person was supposed to get off. This tells us that the original number of people is NOT 128 - this number is too big. So Answer A is NOT correct AND we know that there needs to be fewer people at the beginning. Since Answer A gives us double the number of people getting off at the 7th stop, it's likely that starting with HALF of 128 will give us the correct answer.

If you create the same table (above), but start with the number 64, you will have 1 person getting off the bus at the 7th stop. This is a match for what the question describes.

Final Answer: B

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by GMATGuruNY » Wed Oct 08, 2014 8:06 pm
chacha0212 wrote:Half the people on a bus get off at each stop after the first, and no one gets on after the first stop. If only one person gets off at stop number 7, how many people got on at the first stop?

A. 128
B. 64
C. 32
D. 16
E. 8
The number of people at the CURRENT stop is always HALF the number of people at the PRECEDING stop.
Implication:
The number of people at the PRECEDING stop must be TWICE the number of people at the CURRENT stop.

Working backwards from Stop 7, we get:
Stop 7 = 1 person.
Stop 6 = 2 people.
Stop 5 = 4 people.
Stop 4 = 8 people.
Stop 3 = 16 people.
Stop 2 = 32 people.
Stop 1 = 64 people.

The correct answer is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by Abhishek009 » Thu Oct 09, 2014 9:33 am
chacha0212 wrote:Half the people on a bus get off at each stop after the first, and no one gets on after the first stop. If only one person gets off at stop number 7, how many people got on at the first stop?

A. 128
B. 64
C. 32
D. 16
E. 8

Could you please help on this question? The answer says B and I did not understand the explanation.

Thanks!
Plugging in value works best here ,

Since we gotta simultaneously calculate value till 7th stop it's better for us to assume a number which can be divided by 7 .

The best number possible is ( 2^7 )

Keep dividing -

Stop 1 - 128

Stop 2 - 64

Stop 3 - 32

Stop 4 - 16

Stop 5 - 8

Stop 6 - 4

Stop 7 - 2 Represented as 1

Thus we have taken 2 extra and we gotta divide total by 2 to get the answer 128 /2 = 64.
Abhishek
Join the discussion