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Inequalities- concept

Expert replies
by ikaplan » Sun Jul 27, 2014 5:47 am
I am trying to keep a 'Paraphrase Sheet' for DS, and I ran across the following condition:

w^2>1

I am not good at inequalities, so if someone could explain the logic behind this statement that would be great.

My reasoning: w^2-1>0, (w-1)*(w+1)>0 so there are 2 solutions: w>1, w>-1 (

My question: Do I put AND or OR between solutions number 1 or 2? Any concrete example is more than welcomed.

Thank you~
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Source: — Data Sufficiency |

by GMATinsight » Sun Jul 27, 2014 5:57 am
ikaplan wrote:I am trying to keep a 'Paraphrase Sheet' for DS, and I ran across the following condition:

w^2>1

I am not good at inequalities, so if someone could explain the logic behind this statement that would be great.

My reasoning: w^2-1>0, (w-1)*(w+1)>0 so there are 2 solutions: w>1, w>-1 (

My question: Do I put AND or OR between solutions number 1 or 2? Any concrete example is more than welcomed.

Thank you~
Red Highlighted part is the wrong Reasoning

We should be looking at the correct reasoning in this way

W^2 > 1

i.e. w^2-1>0,
i.e.(w-1)x(w+1)>0
Product of two numbers (w-1) and (w+1) is Greater than 0
i.e. Either Both are Positive
i.e. (w-1)>0 as well as (w+1)>0
i.e. (w)>1 as well as (w)>-1
i.e. w must be greater than 1 to satisfy both the conditions


Or Both are Negative
i.e. (w-1)<0 as well as (w+1)<0
i.e. (w)<1 as well as (w)<-1
i.e. w must be Lesser than -1 to satisfy both the conditions


Therefore the correct range of the values is
W<-1 or W>1
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by GMATinsight » Sun Jul 27, 2014 6:01 am
ALTERNATELY YOU CAN ALSO THINK ABOUT THIS PROBLEM THIS WAY

W^2 > 1

Square of any number will be Greater than 1 only when the Absolute Value of the number is Greater than 1

i.e. /W/ > 1
i.e. Either W>1 or W<-1
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by GMATinsight » Sun Jul 27, 2014 6:13 am
Please refer to the attached DS question whose statement 1 is of such a type that has been solved logically without algebraic calculations
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Solution 1.jpg
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by GMATinsight » Sun Jul 27, 2014 6:19 am
Please check the Solution of a Quadratic Inequation.
Attachments
Inequality of Quadratic.jpg
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by GMATGuruNY » Sun Jul 27, 2014 6:37 am
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by ikaplan » Sun Jul 27, 2014 6:56 am
Thank you for the links GMATGuruNY.

I really need to brush up and build on my skills for inequalities issues. I'll make sure to go over each link in great detail.

Thanks~
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