profit and loss

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by Uva@90 » Sun Jan 05, 2014 3:28 am
[email protected] wrote:Pls show me the solution with the required equation-Thanks
Hi Shibsriz,
Let cost of first car be X
and second one be Y

He sold the first car with profit of 25 %
so 125/100*X = 20,000 => X = 16,000

He sold the second car with loss of 20 %
so, 80/100*Y =20,000 => Y = 25,000

So purchased both the card for amount of 41,000
But he sold the both for 20,000*2 = 40,000

He faced a loss of 1,000.

Hence answer is C

Regards,
Uva.
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by GMATGuruNY » Sun Jan 05, 2014 3:29 am
A used car dealer sold one car at a profit of 25 percent of the dealers purchase price for that car and sold another car at a loss of 20 percent of the dealers purchase price for that car. If the dealer sold each car for $20,000 , what was the dealers total profit or loss, in dollars, for the two transactions combined?

A. 1000 profit
B. 2000 profit
C. 1000 loss
D. 2000 loss
E. 3334 loss
Percentage problems on the GMAT tend to involve very ROUND numbers.

Car 1 earns a 25% profit.
Here, the purchase price must be LESS than 20,000.
Make a list of options:
15000, 16000, 17000, 18000, 19000.
Adding a mark-up of 25% to the value in red yields a selling price of 20,000:
16000 + .25(16000) = 16000 + 4000 = 20,000.
Thus, the purchase price of Car 1 = 16,000.

Car 2 earns a 20% loss.
Here, the purchase price must be MORE than 20,000.
Make a list of options:
21000, 22000, 23000, 24000, 25000.
Subtracting 20% from the value in red yields a selling price of 20,000:
25000 - .2(25000) = 25000 - 5000 = 20,000.
Thus, the purchase price of Car 2 = 25,000.

Sum of the purchase prices = 16000 + 25000 = 41,000.
Sum of the selling prices = 20000 + 20000 = 40,000.
Resulting LOSS = 41000 - 40000 = 1000.

The correct answer is C.

Algebraically:

A profit of 25% implies that the $20,000 selling price is equal to 125% of the purchase price:
20000 = (125/100)x
20000 = (5/4)x
80000 = 5x
x = 16,000.

A loss of 20% implies that the $20,000 selling price is equal to 80% of the purchase price:
20000 = (80/100)y
20000 = (4/5)y
100000 = 4y
y = 25,000.

Sum of the purchase prices = 16000 + 25000 = 41,000.
Sum of the selling prices = 20000 + 20000 = 40,000.
Resulting LOSS = 41000 - 40000 = 1000.
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