BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Factors

Expert replies
by kop » Tue Dec 17, 2013 2:27 am
Is P divisible by 168??

1) p is divisible by 14
2) p is divisible by 12

Please explain? I solved by taking out prime factors , with that i concluded both statements are enough to answer the question, but that's wrong? . Please explain
Join the discussion
Source: — Data Sufficiency |

by Brent@GMATPrepNow » Tue Dec 17, 2013 7:12 am
kop wrote:Is P divisible by 168??

1) p is divisible by 14
2) p is divisible by 12
Target question: Is P divisible by 168?

A lot of integer property questions can be solved using prime factorization.
For questions involving divisibility, divisors, factors and multiples, we can say:
If N is divisible by k, then k is "hiding" within the prime factorization of N

Examples:
24 is divisible by 3 <--> 24 = (2)(2)(2)(3)
70 is divisible by 5 <--> 70 = (2)(5)(7)
330 is divisible by 6 <--> 330 = (2)(3)(5)(11)
56 is divisible by 8 <--> 56 = (2)(2)(2)(7)

So, for P to be divisible by 168, 168 must be hiding in the prime factorization of P.

Since 168 = (2)(2)(2)(3)(7), we need to determine whether there are AT LEAST three 2's, one 3 and one 7 are hiding in the prime factorization of P. So, let's rephrase our target question . . .

REPHRASED target question: Are three 2's, one 3 and one 7 "hiding" in the prime factorization of P?

Statement 1: p is divisible by 14
Since 14 = (2)(7), we can conclude that one 2 and one 7 are "hiding" in the prime factorization of P.
So, we can't be certain whether or not three 2's, one 3 and one 7 are hiding in the prime factorization of P
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: p is divisible by 12
Since 12 = (2)(2)(3), we can conclude that two 2's and one 3 are "hiding" in the prime factorization of P.
So, we can't be certain whether or not three 2's, one 3 and one 7 are hiding in the prime factorization of P
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that one 2 and one 7 are "hiding" in the prime factorization of P.
Statement 2 tells us that two 2's and one 3 are "hiding" in the prime factorization of P.
So, we can conclude that there are at least TWO 2's, one 3 and one 7 "hiding" in the prime factorization of P.
HOWEVER, our goal is to determine whether there are THREE 2's, one 3 and one 7 "hiding" in the prime factorization of P.
So, we can't be certain whether or not three 2's, one 3 and one 7 are hiding in the prime factorization of P
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer = E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by Uva@90 » Tue Dec 17, 2013 7:16 am
kop wrote:Is P divisible by 168??

1) p is divisible by 14
2) p is divisible by 12

Please explain? I solved by taking out prime factors , with that i concluded both statements are enough to answer the question, but that's wrong? . Please explain
Hi Kop,
What you started is correct,
first do the prime factorization,
168 = 2*2*2*3*7
So, Number should have at least three 2's and one 3 and one 7 for divisible by 168.

Statement 1: 14 =2*7
Insufficient.

Statement 2: 12 = 2*2*3
Insufficient.

Combine 1 + 2:
Multiple of both 14 and 12.

Important thing to note here is check both numbers have common factors or not.

Yes it have 14 =2*7 and 12 = 2*2*3

we can number is divisible by 84 = 2*7*2*3 but
we can't say for sure that it is divisible by 168

Hence Insufficient.

Answer is E

Regards,
Uva.
Known is a drop Unknown is an Ocean
Join the discussion

by Brent@GMATPrepNow » Tue Dec 17, 2013 7:16 am
kop wrote:Is P divisible by 168??

1) p is divisible by 14
2) p is divisible by 12
Another approach is to look for counterexamples...

Target question: Is P divisible by 168?
NOTE: 168 = (2)(2)(2)(3)(7)

Statement 1: p is divisible by 14
There are several values of P that satisfy this condition. Here are two:
Case a: P = 168, in which case P is divisible by 168
Case b: P = 84, in which case P is NOT divisible by 168
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: p is divisible by 12
There are several values of P that satisfy this condition. Here are two:
Case a: P = 168, in which case P is divisible by 168
Case b: P = 84, in which case P is NOT divisible by 168
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
There are several values of P that satisfy this condition. Here are two:
Case a: P = 168, in which case P is divisible by 168
Case b: P = 84, in which case P is NOT divisible by 168
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer = E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion