need help

[sana.noor]

Triangle ABC and Triangle CDF has angle a = angle c , angle d = angle b and angle c = angle f. the area of triangle cdf is twice the area of triangle ABC. if the base of triangle ABC is s,and the base of triangle CDF is S, then in terms of s, S =

1. sqrt(2)/2 s
2. sqrt(3)/2 s
3. sqrt(2)s
4. sqrt(3)s
5. 2s

OA is 3

[[email protected]]

Hi sana.noor,

This question is a high-level multi-shape geometry question that involves similar triangles. It's rare and usually worth very little (or nothing) to your overall Quant score. To solve it, try using the Empowergmat tactic TEST IT:

First draw a triangle (you'll find using a right triangle to be easiest). Now, pick a base and a height.

As an example, pick a base of 4 and a height of 3. It's area = .5(4)(3) = 6

Since the second triangle has the SAME ANGLES and an area that's twice as big, it's area = 12

So you have to go from an area of 6 to an area of 12 AND use similar triangles (which means that the side lengths of the big triangle are all proportionately bigger than the smaller triangle).

This means that the base(root2) x height(root2) would account for the "double area"

If the base of the small triangle is s, then the base of the big triangle would be s(root2).

Final Answer C

GMAT assassins aren't born, they're made,
Rich

[GMATGuruNY]

Check here for my solution to a very similar problem from GMAT Prep:

https://www.beatthegmat.com/2-triangles-t75268.html

[faraz_jeddah]

Hi sana.noor,

This question is a high-level multi-shape geometry question that involves similar triangles. It's rare and usually worth very little (or nothing) to your overall Quant score.
Rich

Hi Rich. Out of curiosity, where did you find that information?

[[email protected]]

Triangle ABC and Triangle CDF has angle a = angle c , angle d = angle b and angle c = angle f. the area of triangle cdf is twice the area of triangle ABC. if the base of triangle ABC is s,and the base of triangle CDF is S, then in terms of s, S =

1. sqrt(2)/2 s
2. sqrt(3)/2 s
3. sqrt(2)s
4. sqrt(3)s
5. 2s

OA is 3

An alternate way is to use the property of Similar Triangles and their corresponding areas.

ie if we know the similarity ratio, we can square this ratio to determine ratio of the triangles' areas.

In this case:

Step 1) s/S is the Similarity Ratio.

Step 2) Take the Square of the Similarity Ratio ie (s/S)^2

Step 3) Equate the above value to the ratio of the Areas of Triangles ie (s/S)^2 = 1/2

Solving this Equation we get S= sqrt(2)s.