mv<pv<0
i.e. mv is negative
either m or v is negative
pv is also negative, hence either p or v is negative.
question: v>0 or is v positive?
St 1 m<p
mv<pv<0 only if m and p are negative
(you can prove this by plugging numbers where both m and p are negative and one where only v is negative)
SUFF
St 2 m<0 hence m and p both are negative so v has to be positive
SUFF
Answer is D
Hope the solution is clear
ds-gmatprep
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rhymes_with_luck
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we have three inequalities disguised here
mv<pv or (m-p)v<0
mv<0 and pv<0
from 1 m-p<0 hence in (m-p)v<0; v>0 suff
from 2 m<0 hence in mv<0; v>0 suff
hence D
mv<pv or (m-p)v<0
mv<0 and pv<0
from 1 m-p<0 hence in (m-p)v<0; v>0 suff
from 2 m<0 hence in mv<0; v>0 suff
hence D
