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AVERAGES PROBLEM

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AVERAGES PROBLEM

by amitdgr » Fri Aug 01, 2008 6:54 pm
Q) Of five numbers, first is thrice the third, fourth is two less then the first, fifth is one-seventh of the second and the second is three less then thrice the first. find the fifth number, if the average of the numbers is 16.2.

A) 3
B) 4
C) 5
D) 6
E) 7


Please help. I will post the correct answer later.

Thanks
Amit
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by sudhir3127 » Fri Aug 01, 2008 9:57 pm
Answer is 6...

here it goes..

Assume 3rd number = x
first = 3x
second = 9x-3
fourth = 3x-2
5th = 1/7( 9x-3)

( x+ 3x+ 9x-3+ 3x-2+ 1/7( 9x-3))/5 = 16.2

solve for x .. X = 5

hence the 5th number is (9*5-3)/7= 6

hope it helps..
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by amitdgr » Sat Aug 02, 2008 6:51 am
@ sudhir3127 - Thats the right answer buddy ... thanks for your help :)
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