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nadontheway
- Senior | Next Rank: 100 Posts
- Posts: 88
- Joined: Fri Nov 16, 2007 2:05 am
If you take the three vertices as
A(0,0)
B(6,0)
C(x,y)
and center is T(3,2)
u can form equation as codinates of T ((0+6+x/3)=3 , ((0+0+y)/3)=2)
solve the equation , u will get (x,y) ..ie C(x,y)
C(3,6)
hence B
thx
