BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Sets problem - 1

Expert replies
by guerrero » Fri Mar 29, 2013 3:20 am
A group of Republicans and Democrats was surveyed and each member was asked whether they liked apple pies or éclairs. 80% of the Republicans liked apple pie, 55% of the Democrats liked eclairs, and 20% of the Republicans who liked apple pie also liked eclairs. If the number of Republicans who liked both desserts is equal to the number of Democrats who liked éclairs, what is one possible value for the number of members of the group?

A. 81
B. 88
C. 160
D. 550
E. 710


can we solve it using double matrix method ?

OA E
Join the discussion
Source: — Problem Solving |

by GMATGuruNY » Fri Mar 29, 2013 7:16 am
guerrero wrote:A group of Republicans and Democrats was surveyed and each member was asked whether they liked apple pies or éclairs. 80% of the Republicans liked apple pie, 55% of the Democrats liked eclairs, and 20% of the Republicans who liked apple pie also liked eclairs. If the number of Republicans who liked both desserts is equal to the number of Democrats who liked éclairs, what is one possible value for the number of members of the group?

A. 81
B. 88
C. 160
D. 550
E. 710
Since this is really a problem about RATIOS, I wouldn't use a matrix here.
To determine the least possible value for the total number of members, plug in the least possible value for the total number of Democrats.

55% of the Democrats liked eclairs.
Since 55/100 = 11/20, the total number of Democrats must be a multiple of 20.

Case 1: Total democrats = 20.
Since 55% liked eclairs, the number of Democrats who liked eclairs = 11/20 * 20 = 11.

The number of Republicans who liked both desserts is equal to the number of Democrats who liked éclairs.
Thus, Republicans who liked both = 11.

20% of the Republicans who liked apple pie also liked eclairs.
Thus, the 11 Republicans who liked both are equal to 20% -- or 1/5 - of the total number of Republicans who liked apple pie:
11 = (1/5)x
x=55.

80% of the Republicans liked apple pie.
Thus, the 55 Republicans who liked apple pie are equal to 80% -- or 4/5 -- of the total number of Republicans:
55 = (4/5)y
y = 275/4.

Resulting sums:
Total Democrats = 20 and total Republicans = 275/4.

The total number of Republicans must be an INTEGER.
Thus, ALL of the values in Case 1 -- including the total number of Democrats -- must be multiplied AT LEAST BY A FACTOR OF 4:
Least total Democrats = 4*20 = 80.
Least total Republicans = 4 * 275/4 = 275.
Least total members = 80+275 = 355.

Thus, the total number of members must be a MULTIPLE OF 355.

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by Brent@GMATPrepNow » Fri Mar 29, 2013 7:48 am
guerrero wrote:
can we solve it using double matrix method ?
To use the technique known as the Double Matrix Method, we need a population in which each member has two criteria associated with it.
Here, there are 3 criteria:
- Republicans or Democrats
- like or don't like apple pie
- like or don't like éclairs

If anyone is interested in learning more about the Double Matrix Method (as well as some practice questions to solve), check out these 3 BTG articles:
- https://www.beatthegmat.com/mba/2011/05/ ... question-1
- https://www.beatthegmat.com/mba/2011/05/ ... question-2
- https://www.beatthegmat.com/mba/2011/05/ ... question-3

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion