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Please take a look at this PS Speed-Time problem.

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by aman88 » Wed Dec 12, 2012 2:42 am
Q: Yesterday it took a certain plane 3 hours to fly from City A to City B at an average speed of 400 miles per hour. Today the same plane flew from City A to City B along the same route at an average speed of 450 miles per hour. How many more yesterday than it took today?

A. 10
B. 15
C. 20
D. 25
E. 30

I reached till this point:
1200/450 = 8/3
OA C
Can someone please let me know how to proceed ahead. I am sure I am missing onto something here.

Thanks.
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by eaakbari » Wed Dec 12, 2012 6:45 am
I prefer making a quick table in DST questions however easy the question. It helps avoid lousy mistakes.

D S T
d 400 3
d 450 t

Distance is the same and & since D = S* T

400 * 3 = 450 * t

Solving for t

t = 3 *400 / 450 = 8/3

Time difference = 3-t = 3 - 8/3 = 1/3 (hours)

1/3 * 60 = 20 minutes

Hence C
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by Brent@GMATPrepNow » Wed Dec 12, 2012 8:07 am
aman88 wrote:Q: Yesterday it took a certain plane 3 hours to fly from City A to City B at an average speed of 400 miles per hour. Today the same plane flew from City A to City B along the same route at an average speed of 450 miles per hour. How many more yesterday than it took today?

A. 10
B. 15
C. 20
D. 25
E. 30
You're missing part of the question. Presumably, we want to find out how many minutes more the first trip was.

First find the distance from A to B
Distance = (rate)(time)
= (400)(3)
= 1200 miles

Now find the time for the second trip.
Time = (distance)/(rate)
= 1200/450
= 8/3 hours
= 2 2/3 hours

So, the first trip took 3 hours, and the second trip took 2 2/3 hours.
So, the first trip took 1/3 hours longer.
1/3 hours = [spoiler]20 minutes = C[/spoiler]

Cheers,
Brent
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by puneetkhurana2000 » Wed Dec 12, 2012 9:17 am
Distance between City A and City B will be same in both the cases, so

Distance in Case 1 = Distance in Case 2

400*3 = 450*t, solving for t we get t = 8/3

Difference in times = 3-(8/3) = 1/3 of an hour i.e. 20 minutes.
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by GMATGuruNY » Wed Dec 12, 2012 12:10 pm
aman88 wrote:Q: Yesterday it took a certain plane 3 hours to fly from City A to City B at an average speed of 400 miles per hour. Today the same plane flew from City A to City B along the same route at an average speed of 450 miles per hour. How many more yesterday than it took today?

A. 10
B. 15
C. 20
D. 25
E. 30
Faster rate : slower rate = 450/400 = 9/8.
Since rate and time are RECIPROCALS, faster time : slower time = 8/9.
Since the faster time is 8/9 of the slower time, the faster time requires 1/9 fewer minutes than the slower time (180 minutes):
(1/9)180 = 20.

The correct answer is C.
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by aman88 » Thu Dec 13, 2012 5:35 am
Thank you so much guys. This problem seems easy now, after all your explanations. Much appreciated.
:)
This forum rocks!!
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