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by HalifaxGuy » Mon Oct 22, 2012 4:18 pm
If t= 1/(2^9 * 5^3) is expressed as a terminating decimal, how many zeros will t have between the decimal point and the first non zero digit to the right of the decimal point?

answer is B which is 4 how come?

when i solve it i get 3.
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Source: — Problem Solving |

by GMATGuruNY » Mon Oct 22, 2012 5:13 pm
If t= 1/(2^9 * 5^3) is expressed as a terminating decimal, how many zeros will t have between the decimal point and the first non zero digit to the right of the decimal point?

A - THREE

B - FOUR

C - FIVE

D - SIX

E - NINE

Determine how many powers of 10 are in the denominator.

1/(2�*5³) = 1 / (2�)(2³*5³) = 1/(64*10³) = 1/64,000.

Image

There are four 0's to the right of the decimal.

The correct answer is B.
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