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Is X>Y GEOMETRY

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by pappueshwar » Sun Mar 18, 2012 1:14 am
Points A, B, C and D lie on a circle of radius 1. Let x be the length of arc AB and y the length of arc CD respectively, such that X < PIE and Y < PIE . Is X>Y ?

1. ANGLE ADB is acute
2. ANGLE ADB > ANGLE CAD

pls assist in understanding this . OA IS B
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Source: — Data Sufficiency |
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by Jim@StratusPrep » Mon Mar 19, 2012 6:33 am
The measure of the central angle is equal to the measure in degrees of the arc created by the central angle. Degree measures of arcs can be converted to distances by multiplying diameter x ( measure/360)
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by pappueshwar » Mon Mar 19, 2012 7:01 am
hi JIm,
sorry did not understand the problem
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by GMATGuruNY » Tue Mar 20, 2012 6:27 pm
pappueshwar wrote:Points A, B, C and D lie on a circle of radius 1. Let x be the length of arc AB and y the length of arc CD respectively, such that X < PIE and Y < PIE . Is X>Y ?

1. ANGLE ADB is acute
2. ANGLE ADB > ANGLE CAD

pls assist in understanding this . OA IS B
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An inscribed angle is formed by two chords.

In the figure above:
Inscribed ∠ADB intercepts arc AB.
Inscribed ∠CAD intercepts arc CD.

A GREATER inscribed angle intercepts a GREATER FRACTION of the circumference.
In the figure above:
∠ADB > ∠CAD.
The result is that AB > CD.

Put simply:
The GREATER the inscribed angle, the LONGER the intercepted arc.

Question rephrased: Is ∠ADB > ∠CAD?

Statement 1: ∠ADB is acute
No information about ∠CAD.
INSUFFICIENT.

Statement 2: ∠ADB > ∠CAD
SUFFICIENT.

The correct answer is B.
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by rahulvsd » Wed Mar 21, 2012 7:42 am
Thanks a lot Mitch.
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by AbhiJ » Sun Sep 30, 2012 10:42 am
The answer is C.
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