BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

The value of B ?

Expert replies
Source: — Data Sufficiency |

by everything's eventual » Mon Sep 17, 2012 2:25 am
hmmm..I am not sure how you did it...but this was my method :

Statement 1) is def not sufficient.

Statement 2) says c = 36 = 3^2 * 2^2

Equating both sides we get (5^4)^b = 2

Then we get b = 0 and 2) should be sufficient.
Join the discussion

by vk_vinayak » Mon Sep 17, 2012 2:47 am
avik.ch wrote:If 3^a4^b = c, what is the value of b?

(1) 5a = 25

(2) c = 36

OA = C

I think the second statement is sufficient.

Source : Kaplan
1) Tells us about only a. INSUF

2) (3^a) * (4^b) = 36 = (3^2) * (4^1) => b=1. SUF.
- VK

I will (Learn. Recognize. Apply)
Join the discussion

by avik.ch » Mon Sep 17, 2012 2:57 am
So we can reasonably conclude that the OA is wrong.

Thanks !!
Join the discussion

by avik.ch » Mon Sep 17, 2012 2:59 am
everything's eventual wrote:
Statement 2) says c = 36 = 3^2 * 2^2

Equating both sides we get (5^4)^b = 2

Then we get b = 0 and 2) should be sufficient.
I am not sure how you are getting b=0 ?? Can you please elaborate !!
Join the discussion

by vk_vinayak » Mon Sep 17, 2012 3:20 am
avik.ch wrote:So we can reasonably conclude that the OA is wrong.

Thanks !!
I searched for this question, and found that OA is technically correct, but the question is incomplete. Refer Stewart's explanation at: https://www.beatthegmat.com/a-data-from- ... 81048.html

B is the logical answer.
- VK

I will (Learn. Recognize. Apply)
Join the discussion

by imskpwr » Mon Sep 17, 2012 6:05 am
avik.ch wrote:If 3^a4^b = c, what is the value of b?

(1) 5a = 25

(2) c = 36

OA = C

I think the second statement is sufficient.

Source : Kaplan
At first, I was a bit skeptical as we don't know anything about the RANGE of a and b, but now i am sure now that it's a trick q.

I mean a and b could be integers or non integers; rationals or irrationals;etc.

But once we know that a=2(integer), we can say Definitely that b has to be an integer to satisfy the equation(3^a4^b = c) for c=36.

Hence, BOTH STATEMENTS ARE REQUIRED TO ANSWER.
From 2, we cannot deduce that a and b are only "whole numbers". There may be other values which can satisfy the equation....this would be easier if you think of a solution where a and b are not whole numbers.

This must be a VERY HIGH LEVEL Q.....probably when one is in 50s....and when you are at that level you don't get peanuts so beware of such qs at that level.
I don't think GMAT ask such qs, But Indian CAT do throw such q at you.
Join the discussion

by everything's eventual » Mon Sep 17, 2012 5:44 pm

everything's eventual wrote:
Statement 2) says c = 36 = 3^2 * 2^2

Equating both sides we get (5^4)^b = 2

Then we get b = 0 and 2) should be sufficient.

I am not sure how you are getting b=0 ?? Can you please elaborate !!


Hello, I messed up the whole question. Sorry. I had a brain freeze.

First of all I understood the question as follows :

[3 ^ (a^4)]^ b = c

Statement 2) says c = 36 = 3^2 * 2^2

So comparing original equation and value of C, we get (a^4)^b = 2

Now we cannot solve the above equation unless we know the value of a. From statement 1) we get a= 5.

Therefore, (5^4)^b = 2 and so b = 0.

So yes, according to my flawed explanation the answer is C.
Join the discussion