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At a loading dock

Expert replies
by alex.gellatly » Sun Sep 02, 2012 8:01 pm
At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day day crew, what fraction of all the boxes loaded by the two crews did the day crew load?

1/2
2/5
3/5
4/5
5/8

Thanks
A useful website I found that has every quant OG video explanation:

https://www.beatthegmat.com/useful-websi ... tml#475231
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Source: — Problem Solving |

by adthedaddy » Sun Sep 02, 2012 10:27 pm
Refer this post: https://www.beatthegmat.com/og-problem-138-t25203.html

Multiple ways to solve this problem are indicated.
"Your time is limited, so don't waste it living someone else's life. Don't be trapped by dogma - which is living with the results of other people's thinking. Don't let the noise of others' opinions drown out your own inner voice. And most important, have the courage to follow your heart and intuition. They somehow already know what you truly want to become. Everything else is secondary" - Steve Jobs
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by GMATGuruNY » Mon Sep 03, 2012 5:17 pm
alex.gellatly wrote:At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day day crew, what fraction of all the boxes loaded by the two crews did the day crew load?

1/2
2/5
3/5
4/5
5/8

Thanks
Plug in SMALL numbers.

Day crew:
Let the number of workers = 5.
Let the number of boxes loaded by each worker = 4.
Total number of boxes loaded = 5*4 = 20.

Night crew:
Since the night crew has 4/5 as many workers as the day crew, the number of workers on the night crew = (4/5)5 = 4.
Since each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew, the number of boxes loaded by each night crew worker = (3/4)4 = 3.
Total number of boxes loaded = 4*3 = 12.

(Boxes loaded by the day crew)/(Total number of boxes loaded by the two crews) = 20/(20+12) = 20/32 = 5/8.

The correct answer is E.
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by Anurag@Gurome » Mon Sep 03, 2012 7:44 pm
alex.gellatly wrote:At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. If the night crew has 4/5 as many workers as the day day crew, what fraction of all the boxes loaded by the two crews did the day crew load?

1/2
2/5
3/5
4/5
5/8

Thanks
Say, number of workers in the day crew = w
=> Number of workers in the night crew = 4w/5.

Say, total number of boxes loaded by the day crew = x
=> Number of boxes loaded by each of the workers in the day crew = x/w.
=> Number of boxes loaded by each of the workers in the night crew = (3/4)*(x/w).
=> Total number of boxes loaded by the night crew = Number of workers in the night crew * Boxes loaded by each of the workers in the night crew = (4w/5)*[(3/4)*(x/w)] = 3x/5.

Therefore, total number of boxes loaded by the two crews = Boxes loaded by the day crew + Boxes loaded by the night crew = x + 3x/5 = 8x/5.

Therefore, required fraction = Boxes loaded by the day crew/Total number of boxes loaded by the two crews = x/(8x/5) = [spoiler]5/8[/spoiler].

The correct answer is E.
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