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bucket

Expert replies
by grandh01 » Sun Aug 05, 2012 6:18 pm
Marcia's bucket can hold a
maximum of how many liters of
water?
(1) The bucket currently contains 9
liters of water.
(2) If 3 liters of water are added to
the bucket when it is half full of
water, the amount of water in the
bucket will increase by 1/3.
Join the discussion
Source: — Data Sufficiency |

by Anurag@Gurome » Sun Aug 05, 2012 9:04 pm
grandh01 wrote:Marcia's bucket can hold a
maximum of how many liters of
water?
(1) The bucket currently contains 9
liters of water.
(2) If 3 liters of water are added to
the bucket when it is half full of
water, the amount of water in the
bucket will increase by 1/3.
(1) The bucket currently contains 9 liters of water but we do not know the maximum volume of bucket; NOT sufficient.

(2) If 3 liters of water are added to the bucket when it is half full of water, the amount of water in the bucket will increase by 1/3.
Let V be the total volume of the bucket.
Then volume of water in the bucket when it is half full = V/2
When 3 liters of water are added to the bucket, it's current volume = (V/2) +3 = [V/2 * 1/3] + (V/2)
Now we can find the value of V; SUFFICIENT.

The correct answer is B.
Last edited by Anurag@Gurome on Mon Aug 06, 2012 8:09 pm, edited 2 times in total.
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by jaiswalamrita » Mon Aug 06, 2012 9:54 am
Anurag@Gurome wrote:
grandh01 wrote:Marcia's bucket can hold a
maximum of how many liters of
water?
(1) The bucket currently contains 9
liters of water.
(2) If 3 liters of water are added to
the bucket when it is half full of
water, the amount of water in the
bucket will increase by 1/3.
(1) The bucket currently contains 9 liters of water but we do not know the maximum volume of bucket; NOT sufficient.

(2) If 3 liters of water are added to the bucket when it is half full of water, the amount of water in the bucket will increase by 1/3.
Let V be the total volume of the bucket.
Then volume of water in the bucket when it is half full = V/2
When 3 liters of water are added to the bucket, it's current volume = (V/2) + 3 = [V + V/3] * (V/2)
Now we can find the value of V; SUFFICIENT.

The correct answer is C.
I guess you wanted to write B! And if I'm not wrong the equation should have been (V/2) +3 = [V * V/3] + (V/2)
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by GMATGuruNY » Mon Aug 06, 2012 11:22 am
grandh01 wrote:Marcia's bucket can hold a
maximum of how many liters of
water?
(1) The bucket currently contains 9
liters of water.
(2) If 3 liters of water are added to
the bucket when it is half full of
water, the amount of water in the
bucket will increase by 1/3.
Statement 1 is clearly insufficient: the current volume tells us nothing about the capacity of the bucket.
Statement 2 implies that the 3 liters being added are equal to 1/3 of the water in the bucket:
3 = (1/3)w
w = 9.
Since the bucket contains 9 liters and is half-full, the capacity of the bucket is 18 liters.
SUFFICIENT.

The correct answer is B.
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by Anurag@Gurome » Mon Aug 06, 2012 6:59 pm
jaiswalamrita wrote: I guess you wanted to write B! And if I'm not wrong the equation should have been (V/2) +3 = [V * V/3] + (V/2)
Thanks for pointing this, I have edited my reply.
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by gmat60days » Mon Aug 06, 2012 7:16 pm
Anurag ,I think the correct equation is
(V/2) +3 = [V/2 * 1/3] + (V/2)
Join the discussion

by Anurag@Gurome » Mon Aug 06, 2012 8:10 pm
gmat60days wrote:Anurag ,I think the correct equation is
(V/2) +3 = [V/2 * 1/3] + (V/2)
Yes, that's right. Thanks again! Sorry for the typos!
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