exponents

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by eagleeye » Sun Jul 22, 2012 6:40 pm
sndubose85 wrote:i need help with this problem.

5^21 x 4^11 = 2x10^n, what is n? how do i do this problem
Do this by reducing bases to primes.

5^21 * 4^11 = 2*10^n
5^21 * 2^22 = 2*10^n
5^21 * 2^21 *2 = 2* 10^n
5^21 * 2^21 = 10^n
(5*2)^21 = (5*2)^n
21 = n

Cheers :)