- charu_mahajan
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If the lines with equation y=3x+2 contains the point (r,s), then r&s should satisfy the equation of the line.
i.e s=3r+2 (required)
Statement 1
(3r+2-s)(4r+9-s)=0
so either (3r+2-s)=0 or (4r+9-s)=0
from 1st equation we get s=3r+2, which is required.
from 2nd equation we get s=4r+9, which is not required.
Hence the statement is INSUFFICIENT
Statement 2
(4r-6-s)(3r+2-s)=0
We can solve this the same way we did above.
Similarly this statement is also INSUFFICIENT
Combining both the statements
we can equate both the equations
(3r+2-s)(4r+9-s)=(4r-6-s)(3r+2-s)
By assuming (3r+2-s) to be non zero be can cancel it from both the sides.
Now we are left with
(4r+9-s)=(4r-6-s)
=>9=-6 Not true. This means that our previous assumption was wrong and
(3r+2-s) (must be) =0
Hence SUFFICIENT
So the answer is C

















