DS - Consecutive negative integers

[karthikpandian19]

If x and y are consecutive negative integers, is x greater than y?

x + 1 and y - 1 are consecutive negative integers.
x is an even integer

[Anurag@Gurome]

If x and y are consecutive negative integers, is x greater than y?

x + 1 and y - 1 are consecutive negative integers.
x is an even integer

Statement 1: Note that the following pairs are consecutive negative integers,

• x and y
  x and (x + 1)
  y and (y - 1)
  (x + 1) and (y - 1)

This is only possible when x = (y - 1)
Therefore, x < y

Sufficient

Statement 2: This is not enough to draw any relevant conclusion. For example,

• 1. x = -2 and y -1 --> x < y
  2. x = -2 and y = -2 --> x = y
  3. x = -2 and y = -3 --> x > y

Not sufficient

The correct answer is A.

[karthikpandian19]

OA is A

[GMATGuruNY]

If x and y are consecutive negative integers, is x greater than y?

x + 1 and y - 1 are consecutive negative integers.
x is an even integer

The different between consecutive integers is 1.

Statement 1: x+1 and y-1 are consecutive negative integers.
Case 1:
(x+1) - (y-1) = 1.
1 = y-x.
This works: the difference between y and x is 1, satisfying the condition that x and y are consecutive integers.
In this case, y>x.

Case 2:
(y-1) - (x+1) = 1
y-x = 3.
Doesn't work: x and y are not consecutive integers.

Since only Case 1 is possible, y>x.
SUFFICIENT.

Statement 2: x is even.
No information about y.
INSUFFICIENT.

The correct answer is A.

[karthikpandian19]

I am pretty confused with ur explanation on Statement 1 - Case 2.........

Suppose, if -9 & -10 are two consec. intg;

(-9) - (-10) = 1 true
(-10) - (-9) = -1 false but the magnitude / value should be same

But how come it comes to 3, in your explanation???

If x and y are consecutive negative integers, is x greater than y?

x + 1 and y - 1 are consecutive negative integers.
x is an even integer

The different between consecutive integers is 1.

Statement 1: x+1 and y-1 are consecutive negative integers.
Case 1:
(x+1) - (y-1) = 1.
1 = y-x.
This works: the difference between y and x is 1, satisfying the condition that x and y are consecutive integers.
In this case, y>x.

Case 2:
(y-1) - (x+1) = 1
y-x = 3.
Doesn't work: x and y are not consecutive integers.

Since only Case 1 is possible, y>x.
SUFFICIENT.

Statement 2: x is even.
No information about y.
INSUFFICIENT.

The correct answer is A.

[GMATGuruNY]

I am pretty confused with ur explanation on Statement 1 - Case 2.........

Suppose, if -9 & -10 are two consec. intg;

(-9) - (-10) = 1 true
(-10) - (-9) = -1 false but the magnitude / value should be same

But how come it comes to 3, in your explanation???

Statement 1 tells us that (x+1) and (y-1) are consecutive integers.
Thus, there are two possibilities:
Case 1: (x+1) is one more than (y-1).
Case 2: (y-1) is one more than (x+1).

Case 2 implies the following:
(y-1) - (x+1) = 1.
y-x = 3.
Here, x and y are not consecutive integers.
Since the question stem REQUIRES that x and y be consecutive integers, Case 2 is not viable.