BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Problem Solving incorrect sentences?

Expert replies
by neotinx » Thu Jun 21, 2012 5:26 pm
Hello everyone,

My first post here on BeattheGMAT website..

I was reading the question sentences from the 12th OG guide (#99)

On a scale that measures the intensity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3 ?

a. 5
b. 50
c. 10^5 correct
d. 5^10
e. (8^10)-(3^10)


I have interpreted this question in following ways:

The question remains confusing as it implies that the reading is simply 10 times a reading on n+1. By that logic, the equation is:
n+1 = 10n
A reading if 8 is 70 and a reading of 3 is 20. Difference is 50 (choice B), which is WRONG.

The equation should be written as:

n + 1 = 10^n

Per the equation: reading of 8 is 10^7 and reading of 3 is 10^2. The results differ by a factor of 10^5 or [10^7/10^2] = 10^5


This question is really unclear the way it is written. It clearly states 10 'TIMES' the intensity corresponding to the reading of n. This means it should be 10n not 10^n
The language of the question is very confusing...the correct answer is C


I know that the correct answer is C and I should have solved it as 10^n but I just can't grasp the concept. Is it me or the question is phrased incorrectly?
Join the discussion
Source: — Problem Solving |

by eagleeye » Thu Jun 21, 2012 6:27 pm
Hi Neotinx:

Welcome to the BTG community.

The language in this case is fine. You are interpreting it wrongly. The statement says
"The intensity corresponding to" n+1 is 10 times that of n. This means that intensity is related to reading n in some way. In the math world, we would depict such a relationship by
Intensity (I) = f(n) ; where f represents some sort of function.

Now let's look at this particular problem. Keeping in mind that I=f(n), and new intensity is f(n+1)
we are told that f(n+1)=10*f(n) (New Intensity is 10 times the previous intensity). We don't know what f(n) is exactly. But we can still solve questions.

Now expanding the pattern, for n=1,2,3 etc. we see that.
for n=0, f(0+1)=10*f(0) => f(1)=10*f(0)
for n=1, f(1+1)=10*f(1) => f(2)=10*f(1) = 10* (10*f(0)) = 10^2*f(0)
for n=2, f(3)=10*f(2) = 10^3*f(0) etc.
So we can see the pattern.
Then we need to find f(8)/f(3)
It will be (10^8*f(0))/(10^3*f(0)) = 10^5.

Your mistake was assuming that the reading is 10 times the previous reading. The relationship is not between the "reading" but the corresponding "intensities".

To interpret it the way you wanted it to be, it should have said, "the new reading of n+1 equals 10 times the previous reading of n. I am sure (100%), the more you practice such questions, you will get a penchant for setting up the equations correctly. If it's a hard one, there are experts here to help. Good luck.

Let me know if this helps :)
Join the discussion

by neotinx » Thu Jun 21, 2012 9:55 pm
Thank you so much!

Sometimes it's hard to grasp the concept/instruction of a question such as this one!

You just blew my mind with a crystal-clear explanation! Again, thanks a lot
Join the discussion