rk

[R.K]

If 2^n=128,then (2^(n-1))(5^(n-1))=?

[Anurag@Gurome]

If 2^n=128,then (2^(n-1))(5^(n-1))=?

2^n = 128 ---> n = 7

Hence, (2^(n - 1))*(5^(n - 1)) = (2*5)^(n - 1) = 10^(7 - 1) = 10^6 = 1,000,000