- mdavidm_531
- Senior | Next Rank: 100 Posts
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Hi, Experts,
Here's the question:
Source: OG12 Diagnostic test #13
"If s and t are positive integers such that s/t = 64.12, which of the following could be the remainder when s is divided by t?"
(A) 2
(B) 4
(C) 8
(D) 20
(E) 45
Here's my thought process:
1. We know that s = (quotient)(t) + remainder
2. We divide both sides by t. We have s/t = quotient + remainder/t
3. We know that s/t = 64.12
4. We know that s/t = 64.00 + 12/100
5. As such remainder/t = 12/100
6. Isolate t, we have (remainder)(100)/(12) = t
7. Now here's where I got it wrong. I forgot that t should be integer!
8. There could only be one value of r that could make t an integer. That is 45 (we will be able to reduce 12 to 1 when there's 45 in the numerator)
9. Answer: E
I think the lesson here is that WE SHOULD NOT FORGET THE CONDITIONS. This also applies to data sufficiency, where many errors are made because of not satisfying the statements condition.
Here's the question:
Source: OG12 Diagnostic test #13
"If s and t are positive integers such that s/t = 64.12, which of the following could be the remainder when s is divided by t?"
(A) 2
(B) 4
(C) 8
(D) 20
(E) 45
Here's my thought process:
1. We know that s = (quotient)(t) + remainder
2. We divide both sides by t. We have s/t = quotient + remainder/t
3. We know that s/t = 64.12
4. We know that s/t = 64.00 + 12/100
5. As such remainder/t = 12/100
6. Isolate t, we have (remainder)(100)/(12) = t
7. Now here's where I got it wrong. I forgot that t should be integer!
8. There could only be one value of r that could make t an integer. That is 45 (we will be able to reduce 12 to 1 when there's 45 in the numerator)
9. Answer: E
I think the lesson here is that WE SHOULD NOT FORGET THE CONDITIONS. This also applies to data sufficiency, where many errors are made because of not satisfying the statements condition.












