Is q > t ?

[pappueshwar]

Is q > t ?

(1) qp^2 < tp^2

(2) qp^3 > tp^3

dont have the OA . IMO E.

if statement 1 is divided by p^2 on both sides then q < t.
if statement 2 is divided by p^3 on both sides then q > t.

can we approach the problem this way? is it a big blunder ?

[Anurag@Gurome]

Is q > t ?

(1) qp^2 < tp^2

(2) qp^3 > tp^3

dont have the OA . IMO E.

if statement 1 is divided by p^2 on both sides then q < t.
if statement 2 is divided by p^3 on both sides then q > t.

can we approach the problem this way? is it a big blunder ?

(1) qp² < tp²
p² will always be positive, so dividing both sides by p², we get q < t; SUFFICIENT.

(2) qp^3 > tp^3
Here p^3 may or may not be positive, so we cannot divide both sides by p²; NOT sufficient.

The correct answer is A.

Hope that helps.