BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

coordinate geo

Expert replies
by nafiul9090 » Fri Mar 16, 2012 5:49 pm
In the xy- plane, region A consists of all the points (x,y) such that 1-x<2y. is the point (a,b) in the region A?

i) a>2b
ii) b=1

total confused

if i simplifying the inequality thn i found b> (-1/2)a + 1/2 what i do thn??

oa is c
Join the discussion
Source: — Data Sufficiency |

by Neo Anderson » Sat Mar 17, 2012 5:05 am
hey friend, could crack it with coordinate geometry....

the graph of 1-x<2y will appear as in figure (question)...Image

from statement 1 => a>2b we get region shown in figure (statement 1)....
Image
as the new region partly overlaps the original region => hence insufficient

from statement 2=> b=1 we get the region shown in the figure (statement 2)....
Image
as the new region partly overlaps the original region => hence insufficient

taking both together we get the 3rd figure (both statements)
Image
we can see that the region beyond this point( b=1 and a>2) for sure lies on the original region => both together are sufficient to answer the question!! hence c!
Join the discussion

by [email protected] » Sat Mar 17, 2012 5:42 am
Whatever
Neo Anderson
has written as the solution is the correct answer....

there is no other alternative to solve this kind of questions,,,

The correct answer is C. Just be a bit careful in not doing any silly mistakes in these questions...
IT IS TIME TO BEAT THE GMAT

LEARNING, APPLICATION AND TIMING IS THE FACT OF GMAT AND LIFE AS WELL... KEEP PLAYING!!!

Whenever you feel that my post really helped you to learn something new, please press on the 'THANK' button.
Join the discussion

by tomada » Sat Mar 17, 2012 10:51 am
I used an alternative approach. Since our time is heavily constrained, I try to avoid drawing graphs unless absolutely necessary.

Statement 1: a>2b

let's say b=0.
Now, any positive value of 'a' will satisfy Statement 1.

Substituting 'b' for 'y', which we can do since (a,b) corresponds to (x,y), we have the following:

1-x < 2(0), or 1-x < 0.

Another way to say this is "1-a < 0".
If a > 1, this is true.
If 1 > a > 0, this is false

Statement 1 is insufficient.

Statement 2: b=1

Substituting 'b' for 'y', we get the following:

1-x < 2(1), or 1-x < 2

Another way to say this is "1-a < 2"

If a > -1, this is true
If a <= -1, this is false

Statement 2 is insufficient.

Combining the two statements, we know that:

b = 1
a > 2

Another way of saying this is:

y = 1
x > 2

From the original equation (or Statement 2), "1 - x < 2".

Since x > 2, any such value of 'x' will satisfy this statement.

Combining Statements (1) and (2) is sufficient
I'm really old, but I'll never be too old to become more educated.
Join the discussion

by Neo Anderson » Sat Mar 17, 2012 8:27 pm
quite convincing!
thanks for the alternative approach....
Join the discussion

by GMATGuruNY » Sat Mar 17, 2012 9:45 pm
nafiul9090 wrote:In the xy- plane, region A consists of all the points (x,y) such that 1-x<2y. is the point (a,b) in the region A?

i) a>2b
ii) b=1

total confused

if i simplifying the inequality thn i found b> (-1/2)a + 1/2 what i do thn??

oa is c
For (a,b) to be in region A, it must satisfy 1-x < 2y:
1-a < 2b
1 < a + 2b.

Question rephrased: Is a + 2b > 1?

Statement 2: b=1
No information about a.
INSUFFICIENT.

Statement 1: a > 2b
Plugging a=2 and 2b=1 into a+2b > 1, we get:
2 + 1 > 1?
3>1.
YES.

Plugging a=0 and 2b= -1 into a+2b > 1, we get:
0 + (-1) > 1?
-1>1.
NO.

Since in the first case the answer is YES, and in the second case the answer is NO, INSUFFICIENT.

Statement 1 and 2 combined:
Since b=1 and a>2b:
a > 2(1)
a + 2b > 2(1) + 2(1)
a + 2b > 4.
SUFFICIENT.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion