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without sliding

Expert replies
by sanju09 » Thu Feb 09, 2012 4:35 am
How many revolutions will the wheel make, without sliding, to travel a distance of 100 π?
I. The numerical value of the area enclosed by the wheel is same as its circumference.
II. It takes 55 seconds for the wheel to make 25 revolutions, without sliding.




[spoiler]made up by Sanjeev K Saxena for Avenues Abroad[/spoiler]
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

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Source: — Data Sufficiency |

by [email protected] » Thu Feb 09, 2012 7:26 pm
Stmt1.
(pi)r^2=2(pi)r
therefore, r=2 (since r!=0)
So, in revolution it travels 4(pi) distance. To travel 100n distance it will take 25n/(pi) revs.
So not sufficient.
Stmt2.
The wheel takes 55 secs to make 25 rev. No information about how much distance it makes in one revs is given.Not sufficient.

Together:
Also not sufficient.Ans is E.

P.S.- I'm not sure about the "n" in the question. What is the source of this question?
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by sanju09 » Thu Feb 09, 2012 11:27 pm
[email protected] wrote:Stmt1.
(pi)r^2=2(pi)r
therefore, r=2 (since r!=0)
So, in revolution it travels 4(pi) distance. To travel 100n distance it will take 25n/(pi) revs.
So not sufficient.
Stmt2.
The wheel takes 55 secs to make 25 rev. No information about how much distance it makes in one revs is given.Not sufficient.

Together:
Also not sufficient.Ans is E.

P.S.- I'm not sure about the "n" in the question. What is the source of this question?
Ï€ is not n, it's 'pi', please give another try; source is me, very little known on globe!
The mind is everything. What you think you become. -Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
Join the discussion

by rijul007 » Fri Feb 10, 2012 5:44 am
sanju09 wrote:How many revolutions will the wheel make, without sliding, to travel a distance of 100 π?
I. The numerical value of the area enclosed by the wheel is same as its circumference.
II. It takes 55 seconds for the wheel to make 25 revolutions, without sliding.




[spoiler]made up by Sanjeev K Saxena for Avenues Abroad[/spoiler]
I. The numerical value of the area enclosed by the wheel is same as its circumference.
Ï€r*r = 2Ï€r
r = 2

Suff


II. It takes 55 seconds for the wheel to make 25 revolutions, without sliding.

we dont know the circumference,so it is impossible to find out how many revs it would make to travel 100Ï€

Insuff

Option A
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