(1) x + y + z = 6sud21 wrote:
If a = 2, b = 3, c = 5, x = 4, y = 1, z = 1, then a^x * b^y * c^z = (2^4) * (3^1) * (5^1) = 240 > 200
We have taken the smallest possible values in the above example and we are getting the required result greater than 200. This means that a^x * b^y * c^z will always be greater than 200; SUFFICIENT.
(2) a * b * c > 100
If a = 2, b = 5, c = 11 and x = y = z = 1 (since it is not mentioned that x, y, z are different integers), then a^x * b^y * c^z = 110 < 200
If a = 2, b = 5, c = 11 and x = 1, y = 4, z = 1, then a^x * b^y * c^z = 2 * 625 * 11 > 200
No definite answer; NOT sufficient.
The correct answer is A.
