how to do it fast,

[quantskillsgmat]

Each side of a polygon is parallol to X axis or Y axis.A corner of this polygon is convex if internal angle is 90 and concave if interior angle is 270 degrees. If the number of convex corners are 25 in this polygon,then concave must be
a)20 b)0 c)21 d)22

[Anurag@Gurome]

Each side of a polygon is parallol to X axis or Y axis.A corner of this polygon is convex if internal angle is 90 and concave if interior angle is 270 degrees. If the number of convex corners are 25 in this polygon,then concave must be

This can be easily solved without going into much detailed mathematics.

Just note that any polygon such that each of its sides are parallel to parallol to either X axis or Y axis (i.e. all internal angles are either 90 degrees or 270 degrees) will have even number of sides. And hence, even number of corners.

As number of convex corner is ODD, number of concave corners must be EVEN.

Only option C is feasible.

The correct answer is C.

[mankey]

Dear Anurag

Please explain this theorem further, it is still not clear.

Thanks.

[Anurag@Gurome]

Please explain this theorem further...

This is no theorem, just try drawing few polygons for yourself. You'll see that no polygon can be drawn with odd number of sides which will have all the sides parallel to either of the axis.

Refer to the attached figure for better understanding.

[ArunangsuSahu]

@Anurag...This is the formula

25*90+x(-90)=360
x=21