karthikpandian19 wrote:Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win?
5/6
2/3
1/2
5/12
1/3
Is this a simple problem or tough one? Sometimes i get carried away with the info tht the sum is tough
Since it is given that
Jim and Renee have an equal chance of choosing any one of the hand signs, Renee is irrelevant here: she can select whatever sign she wants.
All that matters is what JIM selects RELATIVE TO RENEE.
He has 3 options: rock, paper, scissors.
Of these 3 options, ONLY ONE will result in a win for Jim.
Thus, P(Jim wins) = 1/3.
The correct answer is
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