Stmt 1 - Take bx to LHS. Hence Sufficient.klmehta03 wrote:Is ax = 3 - bx ?
(1) x(a + b) = 3
(2) a = b = 1.5 and x = 1.
Stmt 2 - Input values, hence Sufficient.
Hence D
Stmt 1 - Take bx to LHS. Hence Sufficient.klmehta03 wrote:Is ax = 3 - bx ?
(1) x(a + b) = 3
(2) a = b = 1.5 and x = 1.

(1) x(a + b) = 3 implies ax + bx = 3 or ax = 3 - bx; SUFFICIENT.klmehta03 wrote:Is ax = 3 - bx ?
(1) x(a + b) = 3
(2) a = b = 1.5 and x = 1.