why you think it's wrong q.?
st(1) implies if x is prime then the only prime factor of x is x itself, and x>sqrt(x). But x as non-prime can have a prime factor equal to srt(x) and/or less (not greater). Ex., x=9, factor=3 and 3=sqrt(9). All other non-primes will contain 2 as a prime as well and will be not suitable here. Hence the answer is Yes, x is prime. Sufficient
st(2) implies if x is prime then x>x/2, which is true. If x is non-prime, then it's possible for prime factors of x to be only less than or equal to x/2. Ex., 3<9/2 or 2=4/2 Sufficient
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user123321 wrote:sud21 wrote:Integer x is greater than 0, is x a prime number?
1). All the prime factors of x are greater than root x
2). All the prime factors of x are greater than x/2
Hi
I think there is some issue in the problem.
a prime factor of x cannot be b/w root x and x.
please check once.
Regards,
user123321