BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Greatest Prime Factor

Expert replies
by chieftang » Sun Jan 08, 2012 11:12 am
Let P = 200! + 1.

Then, the greatest prime factor of P must be:

(A) Less than 40
(B) Between 40 and 80
(C) Between 80 and 120
(D) Between 120 and 160
(E) Greater than 160


Source: GMAT Hints
Join the discussion
Source: — Problem Solving |

by LalaB » Sun Jan 08, 2012 11:21 am
imho E is the answ
Join the discussion

by rijul007 » Sun Jan 08, 2012 11:26 am
chieftang wrote:Let P = 200! + 1.

Then, the greatest prime factor of P must be:

(A) Less than 40
(B) Between 40 and 80
(C) Between 80 and 120
(D) Between 120 and 160
(E) Greater than 160


Source: GMAT Hints
IMO E

200! is the product of all integers from 1 to 200...
if we add it by 1.. the no will not be divisible by any integer b/w 1 and 200 inclusive.
Join the discussion

by ronnie1985 » Mon Jan 09, 2012 2:06 am
There is no single approach to solving the problem, but since 200!+1 is 1 greater than 200! which is product of all numbers from 1 to 200 inclusive, I think, the greatest prime divisor should be greater than 160. (E) is the answer.
Follow your passion, Success as perceived by others shall follow you
Join the discussion

by romy » Wed Jan 11, 2012 2:06 am
I think it will be: (E) Greater than 160
Join the discussion

by GMATGuruNY » Wed Jan 11, 2012 7:06 am
chieftang wrote:Let P = 200! + 1.

Then, the greatest prime factor of P must be:

(A) Less than 40
(B) Between 40 and 80
(C) Between 80 and 120
(D) Between 120 and 160
(E) Greater than 160


Source: GMAT Hints
Since the difference between them is 1, P and 200! are consecutive integers. Consecutive integers are COPRIMES: they share no factors other than 1.

Let's examine why:

If x is a multiple of 2, the next largest multiple of 2 is x+2.
If x is a multiple of 3, the next largest multiple of 3 is x+3.

Using this logic, if we go from x to x+1, we get only to the next largest multiple of 1. So 1 is the only factor common to both x and x+1. In other words, any two consecutive integers -- including P and 200! -- are COPRIMES.

200! = 1 * 2 * 3 * 4...198 * 199 * 200.
Every prime number less than 200 is a factor of 200!.
Since P and 200! are COPRIMES -- meaning they share no factors other than 1 -- no prime factor less than 200 can be a factor of P.

Thus, the smallest prime factor of P must be greater than 200.
Since the smallest prime factor of P is greater than 200, so must be the greatest prime factor of P.

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by ArunangsuSahu » Thu Jan 12, 2012 2:56 pm
199 is the greatest Prime that divides 200!

so for 200!+1 it has to be greater than 199

(E) is the answer
Join the discussion